![]() The search process is terminated.When searching for data, the difference between a fast application and a slower one lies in the accurate use of search algorithm. 12) is equal to 12.t the new value is located at position3. In this case, new values of start and end are 3 and 3 (start = mid + 1) respectively. In this case, new values of start and end are 2 and 3 (start = mid +1) respectively. In this case, new values of start and end are 0 and 3 (end = mid-1) respectively. 0 to 3.ĭivide again left side of the array from 0 to 3. 12) exists on the left half side of the array, i.e. In the above case, the value of start is 0, while the end is 9. Suppose we want to search the value 12 in the above array.ĭivide the array into two halves such as mid =(start + end)/2. The following steps explain the binary Searching in C++ for finding a specific value in the above array. Suppose an array “abc” with 10 values in sorted order as shown in the following figure The main purpose of the binary search is to repeatedly cut a given list into two halves with every comparison. If the required value is in the middle of the list then searching process is successful and is stopped at that point otherwise one of two halves of the list is selected for further Searching in C++. In binary searching, the search process is started from the middle of the sorted list. It is used to search large-size list to find a specific value. In C++ as compared to the Sequential searching the binary Searching in C++ is very fast. The Binary searching technique is used to search the desired data value or item in an ordered list(i.e the values sorted in ascending or descending order). This method is not recommended for a large amount of data because some more efficient method is available for large and complex search.Įxample: how to use sequential searching in C++ for search a value in an array list and display their position on the screen: The sequential search is slow and is used for an only a small list of data. The search operation is ended toward the end of the list and is terminated. This value doesn’t exist in the list as given underneath. Assume we need to search 66 in the list of values as appeared in figure. The search cycle proceeds till the value is found or end of the list is reached.
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